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The rate of a particular reaction quadru...

The rate of a particular reaction quadruples when the temperature changes from 293 K to 313 K. Calculate activation energy in KJ/mol.

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To calculate the activation energy (Ea) for the reaction where the rate quadruples when the temperature changes from 293 K to 313 K, we can use the Arrhenius equation in the form of the logarithmic relationship: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Initial temperature, \( T_1 = 293 \, K \) - Final temperature, \( T_2 = 313 \, K \) - The rate quadruples, which means \( \frac{K_2}{K_1} = 4 \). ...
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The rate of a particular reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation for such a reaction.

The rate of a particular reaction quadruples when the temperature changes from 293K to 313 K. Calculate the energy of activation for such a reaction assuming that it does not change with temperature.

Knowledge Check

  • The rate of a reaction quadruples when the temperature changes from 300 to 310 K. The activation energy of this reaction is : (Assume activation energy and pre-exponential factor are independent of temperature, In 2 = 0.693, R=8.314 J mol^(-1) K^(-1) )

    A
    `107.2 kJ mol^(-1)`
    B
    `53.6 kJ mol^(-1)`
    C
    `26.8 kJ mol^(-1)`
    D
    `214.4 kJ mol^(-1)`
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