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Arrange the following complexes in order...

Arrange the following complexes in order of increasing electrical conductivity: `[CO(NH_(3))_(3)Cl_(3)]`, `[Co(NH_(3))_(5)Cl]Cl_(2)`, `[Co(NH_(3))_(6)]Cl_(3)`

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To arrange the given complexes in order of increasing electrical conductivity, we need to consider the number of ions produced when each complex is dissolved in water. Electrical conductivity is directly proportional to the number of ions in solution; the more ions produced, the higher the conductivity. ### Step-by-Step Solution: 1. **Identify the complexes:** - Complex 1: \([Co(NH_3)_3Cl_3]\) - Complex 2: \([Co(NH_3)_5Cl]Cl_2\) - Complex 3: \([Co(NH_3)_6]Cl_3\) ...
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Arrange the following complexes in the increasing order of conductivity of their solution [Co(NH_(3))_(3)Cl_(3)], [Co(NH_(3))_(4)Cl_(2)]Cl, [Co(NH_(3))_(6)]Cl_(3), [Cr(NH_(3))_(5)Cl] Cl_(2)

Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH_(3))_(3)Cl_(3)], [Co(NH_(3))4Cl_(2)]Cl, [Co(NH_(3))_(6)]Cl_(3), [Cr(NH_(3))5Cl]Cl_(2) .

Knowledge Check

  • In a complex, [Co(NH_(3))_(3)Cl_(3)] ,

    A
    C.N. is 6 and oxidation state is +3
    B
    Oxidation number +6 and C.N. is 3
    C
    C.N. is 6 and oxidation state is zero
    D
    Coordination number and oxidation number are 3 and +3 respectively

  • Select similarity between : [Co(NH_(3))_(4)(H_(2)O)Cl]Cl_(2)" and "[Co(NH_(3))_(4)Cl_(2)]Cl.H_(2)O

    A
    Oxidation number and coordination number of metal
    B
    `Cl^(-)" and "H_(2)O` are the ligands
    C
    Amount of precipitate with `AgNO_(3)` solution (by equimolar 1 litre solution both)
    D
    Number of Co-N linkages

  • Select similarity between : [Co(NH_(3))_(4)(H_(2)O)Cl]Cl_(2)" and "[Co(NH_(3))_(4)Cl_(2)]Cl.H_(2)O

    A
    Oxidation number and coordination number of metal
    B
    `Cl^(-)" and "H_(2)O` are the ligands
    C
    Amount of precipitate with `AgNO_(3)` solution (by equimolar 1 litre solution both)
    D
    Number of Co-N linkages

    • Similar Questions

    Explore conceptually related problems

    Arrange the following complexes in the increasing order of conductivity of their solution : [Co(NH_(3))_(3)Cl_(3)],[Co(NH_(3))_(4)Cl_(2)]Cl,[Co(NH_(3))_(6)]Cl_(3),[Cr(NH_(3))_(5)Cl]Cl_(2) .

    Arrange the following in increasing order as directed. (a) (i) [CoCl_(3)(NH_(3))_(3)]," "(ii)[CoCl(NH_(3))_(5)]Cl_(2)," "(iii)[Co(NH_(3))_(6)]Cl_(3), " " (iv) [CoCl_(2)(NH_(3))_(4)]Cl - Molar conductance (b) C,N,O,F (halogen)-tendency of sigma donation. ( c) Br^(-),S^(2-),NO_(2)^(-),CO,CN^(-),NH^(3),NO^(3)^(-) -strength of ligands.

    Arrange the following compounds in the order of decreasing molar conductivity in aqueous solution. i.a. K[Co(NH_(3))_(2)(NO_(2))_(4)] b. [Cr(NH_(3))_(3)(NO_(2))_(3)] c." " [Cr(NH_(3))_(5)(NO_(2))]_(3)[Co(NO_(2))_(6)]_(2) d." "[Mg(Cr(NH_(3)(NO_(2))_(5)] ii. a. Li[Co(NH_(3))_(2)(NO_(2))_(4)]" "b." "Na[Co(NH_(3))_(2)(NO_(2))_(4)] c.K[Co(NH_(3))_(2)(NO_(2))_(4)]" "d." "Cs[Co(NH_(3))_(2)(NO_(2))_(4)] iii. a. Pt(NH_(3))_(6)Cl_(4)"" b." " Cr(NH_(3))_(6)Cl_(3) c." " Co(NH_(3))_(4)Cl_(3)" "d. K_(2)PtCl_(6)

    The total number of unpaired electrons present in [Co(NH_(3))_(6)]Cl_(2) and [Co(NH_(3))_(6)]Cl_(3) is

    IUPAC name of [Co(NH_(3))_(3)(H_(2)O)_(2)Cl]Cl_(2) is

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