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A coordiantion compound has the formula ...

A coordiantion compound has the formula `CoCl_(3).4NH_(3)`. It does not liberate `NH_(3)` but forms a precipitate with `AgNO_(3)` . Write the structure and IUPAC name of the complex compound. Does it show geometrical isomerism?

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AI Generated Solution

To solve the problem step by step, we will analyze the coordination compound with the formula \( \text{CoCl}_3 \cdot 4\text{NH}_3 \). ### Step 1: Identify the Coordination Complex The given formula indicates that cobalt (Co) is the central metal atom, surrounded by three chloride ions (Cl) and four ammonia molecules (NH3). ### Step 2: Determine the Oxidation State of Cobalt To find the oxidation state of cobalt in this complex, we can set up the following equation: ...
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Explore conceptually related problems

In the complex CoCl_(3).4NH_(3)

In the compound CoCl_(3).5NH_(3) :

IUPAC name of the complex CoCl_(3) 5NH_(3) is

Knowledge Check

  • In the complex CoCl_(3).4NH_(3)

    A
    Co-ordiantion entity is `[Co(NH_(3))_(4).Cl_(2)]^(+)`
    B
    Counter ion is `Cl^(-)`
    C
    Both are correct
    D
    None is correct.

  • In the compound CoCl_(3).5NH_(3) :

    A
    all the cl show primary valency (PV) only
    B
    two cl show (PV) and one Cl secondary valency (SV)
    C
    two Cl show (PV) and one Cl (PV) as well as (SV)
    D
    all the Cl show (SV)

  • In the compound CoCl_(3).5NH_(3) :

    A
    all the cl show primary valency (PV) only
    B
    two cl show (PV) and one Cl show secondary valency (SV)
    C
    two Cl show (PV) and one Cl (PV) as well as (SV)
    D
    all the Cl show (SV)