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Calculate the magnetic moments of the fo...

Calculate the magnetic moments of the following complexes: (i) `[Fe(CN)_(6)]^(-4)`
(ii)`[FeF_(6)]^(-3)`

Text Solution

AI Generated Solution

To calculate the magnetic moments of the given complexes, we will follow these steps: ### Step 1: Determine the oxidation state of the metal in each complex. #### (i) For `[Fe(CN)_(6)]^(-4)`: - Let the oxidation state of Fe be \( x \). - The charge of CN is -1, and there are 6 CN ligands, so the total contribution from CN is \( -6 \). - The overall charge of the complex is -4. ...
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The correct order of magnetic moment (spin only) of following compound is : (i) [FeF_6]^(3-) (ii) [Co(CN)_6]^(3-) (iii) [NiCl_4]^(2-) (iv) [Cu(NH_3)_4]^(2+)

Knowledge Check

  • Which of the following is TRUE for [Fe(CN)_(6)]^(3-) and [FeF_(6)]^(3-) ?

    A
    Both are paramagnetic
    B
    `[Fe(CN)_(6)]^(3-)` is paramagnetic and `[FeF_(6)]^(3-)` is diamagnetic.
    C
    `[Fe(CN)_(6)]^(3-)` is diamagnetic and `[FeF_(6)]^(3-)` is paramagnetic
    D
    Both are diamagnetic

  • The complex ions [Fe(CN)_(6)]^(3-) and [Fe(CN)_(6)]^(4-) :

    A
    Are both octahedral and paramagnetic
    B
    Are both octahedral and diamagnetic
    C
    Have same structure but opposite magnetic character
    D
    Have different structure but opposite magnetic character

  • The complex ion [Fe(CN)_(6)]^(4-) contains:

    A
    total of 36 electrons on `Fe^(2+)` cation
    B
    `sp^(3)d^(2)` hybrid orbitals with octahedral structure
    C
    total of 104 electrons
    D
    six sigma bonds

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    Write hybridisation and shape of the following complexes . (i) [FeF_6]^(3-) (ii) [Ni(CO)_4]

    Find the total no. of unpaired e~ present in the following complexes. (i) [Fe(CO)_(5)] , (ii) [Cr(CO)_(6)] (iii) [Fe(CN)_(6)]^(4-) , (iv) [Mn(CN)_(6)]^(4-)

    The complex ion [Fe(CN)_(6)]^(4-) contains:

    In the complex K_(2)Fe[Fe(CN)_(6)] :

    In the complex K_(2)Fe[Fe(CN)_(6)] :

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