Home
Class 12
PHYSICS
The diameter of an objective of a telesc...

The diameter of an objective of a telescope, which can just resolve two stars situated at angular displacement of `10^(-4)` degee, should be `(lambda = 5000 Å)`

A

35 mm

B

35 cm

C

35 m

D

3 . 5 cm

Text Solution

Verified by Experts

The correct Answer is:
B

`theta = (1 . 22 lambda)/(a)`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 1 (H.W) Polarisation|5 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 2 (C . W) Interference|13 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 1 (H.W) Diffraction|3 Videos
  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise ADDITIONAL EXERCISE (ASSERTION AND REASON TYPE QUESTIONS :)|19 Videos

Similar Questions

Explore conceptually related problems

What should be the size of the aperture of the objective of telescope which can just resolve the two stars of angular width of 10^(3) degree by light of wavelength 5000 Å ?

The diameter of objective of a telescope is 1m . Its resolving limit for the light of wave length 4538 Å , will be

Calculate the aperture of the objective of a telescope which may be used to just resolve two stars separated by 6.1 times 10^-6 radian, if light from the star has a wavelength of 550 nm.

Diameter of the objective of a telescope is 200cm. What is the resolving power of a telescope? Take wavelength of light =5000Å.

The diameter of the objective of a telescope is a, its magnifying power is m and wavelength of light is lambda . The resolving power of the telescope is

The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å . Its resolving power would be approximately

Assertion : By increasing the diameter of the objective of telescope, we can increase its range. Reason : The range of a telescope tells us how far away a star of some standard brightness can be spotted by telescope.