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The diameter of an objective of a telesc...

The diameter of an objective of a telescope, which can just resolve two stars situated at angular displacement of `10^(-4)` degee, should be `(lambda = 5000 Å)`

A

35 mm

B

35 cm

C

35 m

D

3 . 5 cm

Text Solution

Verified by Experts

The correct Answer is:
B

`theta = (1 . 22 lambda)/(a)`
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Knowledge Check

  • The diameter of objective of a telescope is 1m . Its resolving limit for the light of wave length 4538 Å , will be

    A
    `5.54xx10^(-7)rad`
    B
    `2.54xx10^(-4)rad`
    C
    `6.54xx10^(-7)rad`
    D
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  • Diameter of the objective of a telescope is 200cm. What is the resolving power of a telescope? Take wavelength of light =5000Å.

    A
    `6.56xx10^(6)`
    B
    `3.28xx10^(5)`
    C
    `1xx10^(6)`
    D
    `3.28xx10^(6)`
  • The diameter objectives of a telescope is a, its magnifying in m and wavelength of light is lambda . The resolving power of the telescope is

    A
    `(1.22lambda)/(a)`
    B
    `(1.22a)/(lambda)`
    C
    `(lambdam)/(1.22a)`
    D
    `(a)/(1.22lambdam)`
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    Calculate the aperture of the objective of a telescope which may be used to just resolve two stars separated by 6.1 times 10^-6 radian, if light from the star has a wavelength of 550 nm.

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