Home
Class 12
PHYSICS
Two coherent sources of intensity ratio ...

Two coherent sources of intensity ratio `beta` interfere, then `(I_(max)-I_(min))/(I_(max)+I_(min))` is

A

`(beta)/(1 + beta)`

B

`(2 sqrt(beta))/(1 + beta)`

C

`(2 sqrt(beta))/(1 + sqrt(beta))`

D

`(2 beta )/( 1 + sqrt(beta))`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 4 Diffraction|2 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 4 Polarisation|9 Videos
  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 3|17 Videos
  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise ADDITIONAL EXERCISE (ASSERTION AND REASON TYPE QUESTIONS :)|19 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources of intensity ratio beta^2 interfere. Then, the value of (I_(max)- I_(min))//(I_(max)+I_(min)) is

Two doherent sources of intensity ratio alpha interfere in interference pattern (I_(max)-I_(min))/(I_(max)+I_(min)) is equal to

The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference patten, the ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be

Two coherent sources of intensity ratio alpha interfere. In interference pattern (I_(max)-I_("min"))/(I_(max)-I_("min")) =

Two coherent sources with intensity ratio alpha interfere. Then, the ratio (l_(max)-l_("min"))/(l_(max)+l_("min")) is

Two coherent sources of intensity ratio alpha interface . In interference pattern (I_("max") - I_("min"))/(I_("max") + I_("min")) =

Two coherent sources of light of intensity ratio beta interfere. Prove that the interference pattern, (I_(max)-I_(min))/(I_(max)+I_(min))=(2sqrtbeta)/(1+beta) .