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A particle oscillates as per the equatio...

A particle oscillates as per the equation `x = (7 cos 0.5 pi t)m`, the time taken by the particle to move from the mean position to a point `3.5m` away is

A

1/3 s

B

1/2 s

C

1s

D

2/3 s

Text Solution

Verified by Experts

The correct Answer is:
A
`A = 7m , x = 3.5 m = (A)/(2)`
`x = 0 rArr = x = (A)/(2)"takes"(T)/(12)` time
`T = (2pi)/(0.5 pi) = 4s rArr t = (4)/(12) = (1)/(3)s`
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Knowledge Check

  • A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

    A
    1 s
    B
    2 s
    C
    `1//2` s
    D
    4 s

  • A particle is oscillating according to the equation x = 7cos(0.5pi t) , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

    A
    `4s`
    B
    `2s`
    C
    `1s`
    D
    `0.5s`

  • A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

    A
    4.0 sec.
    B
    2sec.
    C
    1.0 sec.
    D
    0.5 sec.
    • NARAYNA-OSCILLATIONS-EXERCISE - I (H.W)
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