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The charge required for the reduction of...

The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` is

A

1 F

B

2 F

C

6 F

D

4 F

Text Solution

Verified by Experts

`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+) +7H_(2)O`
1 mol `Cr_(2)O_(7)^(2-)` requires 6 mol of electrons, i.e., 6 Faraday charge
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