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What volume of 3 molar HNO(3) is needed ...

What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(3+)`, `HNO_(3)` gets converted to `NO` ?

A

8 mL

B

16 mL

C

32 mL

D

64 mL

Text Solution

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The correct Answer is:
B
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What volume of 3 M HNO_(3) is needed to oxidize 8 g of Fe^(2+) to Fe^(3+) , HNO_(3) gets converted to NO ?

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Knowledge Check

  • What volume of 3MHNO_(3) is needed to oxidize 8 g Fe(2+)toFe(3+),HNO_(3) of to gets converted to NO ?

    A
    8 Ml
    B
    16 mL
    C
    32 mL
    D
    64 mL

  • HNO_(3) acts as

    A
    Acid
    B
    Oxidising agent
    C
    Reducing agent
    D
    Both (a) and (b)

  • What volume of 0.1 N HNO_(3) solution can be prepared from 6.3 " g of " HNO_(3) ?

    A
    1 litre
    B
    2 litres
    C
    `0.5` litres
    D
    5 litres

    • Similar Questions

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    pH of 10^(-8) M HNO_(3) is (nearly)

    HNO_(3) is manufactured by:

    One mole of As_(2)S_(3) is oxidized by HNO_(3) to H_(3)AsO_(4) and H_(2)SO_(4). HNO_(3) is converted into NO. The moles of HNO_(3) required are :

    What weight of HNO_(3) is needed to convert 62gm of P_(4) in H_(3) PO_(4) in the region ? P_(4) + HNO_(3) rarr H_(3) PO_(4) + NO_(2) + H_(2) O

    The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. One mole of As_(2)S_(3) is oxidised by HNO_(3) to H_(3)AsO_(4) and H_(2)SO_(4).HNO_(3) is converted into NO . The moles of HNO_(3) required are:

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