A bullet of mass 10 gm strikes a target ...

A bullet of mass `10 gm` strikes a target at `400 m//s` velocity and does half of its initial velocity. The loss of kinetic energy in joules is

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The correct Answer is:

`(4)`

`Delta KE = 1/2m(v_(1)^(2) - v_(1)^(2)), v_(2) = v_(1)/2`

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