Find the probability that a leap year will have 53 Friday or 53 Saturdays.

Answer

`(3)/(7)`

Explanation

There are 366 days in a leap year. Also, there are 52 weeks and 2 days.
The prossible combinations of two days are as follows:
Sunday-Monday,
Monday-Tuesday,
Tuesday-Wednesday,
Wednesday-Thursday,
Thurday-Friday,
Friday-Saturday,
Saturday-Sunday
Now, let E be the event in which leap year will have 53 Fridays or 53 Saturdays.
We observe that there are three possibilities for event E, viz. Thursday-Friday, Friday-Saturday, and Saturday-Sunday. Since each pair of 2 equally likely,
`P(E) = (1)/(7) + (1)/(7) + (1)/(7) = (3)/(7)`