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Coefficients of variation of two distrib...

Coefficients of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25, respectively. Difference of their standard deviations is

A

0

B

1

C

1.5

D

2.5

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The correct Answer is:
To solve the problem, we need to find the difference between the standard deviations of two distributions given their coefficients of variation and means. ### Step-by-Step Solution: 1. **Understanding Coefficient of Variation (CV)**: The coefficient of variation is defined as: \[ CV = \frac{\sigma}{\bar{X}} \times 100 \] where \(\sigma\) is the standard deviation and \(\bar{X}\) is the mean. 2. **Setting Up the Equations**: For the first distribution: - Coefficient of Variation \(CV_1 = 50\) - Mean \(\bar{X}_1 = 30\) For the second distribution: - Coefficient of Variation \(CV_2 = 60\) - Mean \(\bar{X}_2 = 25\) 3. **Finding Standard Deviation for the First Distribution**: Using the formula for \(CV_1\): \[ 50 = \frac{\sigma_1}{30} \times 100 \] Rearranging gives: \[ \sigma_1 = \frac{50 \times 30}{100} = 15 \] 4. **Finding Standard Deviation for the Second Distribution**: Using the formula for \(CV_2\): \[ 60 = \frac{\sigma_2}{25} \times 100 \] Rearranging gives: \[ \sigma_2 = \frac{60 \times 25}{100} = 15 \] 5. **Calculating the Difference in Standard Deviations**: Now, we find the difference between the two standard deviations: \[ \sigma_2 - \sigma_1 = 15 - 15 = 0 \] 6. **Conclusion**: The difference of their standard deviations is \(0\). ### Final Answer: The difference of their standard deviations is \(0\). ---

To solve the problem, we need to find the difference between the standard deviations of two distributions given their coefficients of variation and means. ### Step-by-Step Solution: 1. **Understanding Coefficient of Variation (CV)**: The coefficient of variation is defined as: \[ CV = \frac{\sigma}{\bar{X}} \times 100 ...
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CENGAGE-STATISTICS-Exercise (Single)
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  14. The harmonic mean of 4,8,16 is

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  16. The following data gives the distribution of height of students : {:...

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  17. For a slightly asymmetric distribution, mean and medain are 5 and 6, r...

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  19. If mu the mean of distribution (y(i),f(i)), then sum f(i)(y(i)-mu)=

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