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Find general solution of tanx=sqrt(3)...

Find general solution of `tanx=sqrt(3)`

A

`x=npi+pi/6`

B

`x=npi+pi/3`

C

`x=npi+-pi/6`

D

`x=npi+-pi/3`

Text Solution

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The correct Answer is:
To find the general solution of the equation \( \tan x = \sqrt{3} \), we can follow these steps: ### Step 1: Identify the reference angle We know that \( \tan \frac{\pi}{3} = \sqrt{3} \). Therefore, the reference angle for our equation is: \[ x = \frac{\pi}{3} \] ### Step 2: Consider the periodic nature of the tangent function The tangent function has a period of \( \pi \). This means that if \( x = \frac{\pi}{3} \) is a solution, then all solutions can be expressed in the form: \[ x = \frac{\pi}{3} + n\pi \] where \( n \) is any integer. ### Step 3: Write the general solution Thus, the general solution for the equation \( \tan x = \sqrt{3} \) is: \[ x = \frac{\pi}{3} + n\pi, \quad n \in \mathbb{Z} \] ### Summary The general solution of \( \tan x = \sqrt{3} \) is: \[ x = \frac{\pi}{3} + n\pi, \quad n \in \mathbb{Z} \] ---

To find the general solution of the equation \( \tan x = \sqrt{3} \), we can follow these steps: ### Step 1: Identify the reference angle We know that \( \tan \frac{\pi}{3} = \sqrt{3} \). Therefore, the reference angle for our equation is: \[ x = \frac{\pi}{3} \] ...
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Knowledge Check

  • General solution of sinx=tanx

    A
    `(npi)/(2)`
    B
    `n pi+(pi/4)`
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    ` (3n pi)/(2)`
    D
    `2n pi`
  • General solution of secx=sqrt(2) is

    A
    `2npipm(7pi)/(4), ninZ`
    B
    `2npipm(pi)/(4), ninZ`
    C
    `4npipm(7pi)/(2), ninZ`
    D
    `4npipm(pi)/(2), ninZ`
  • Find the general solution of tan 3x = 1 is-

    A
    `n pi + (pi)/(4)`
    B
    `(npi)/(3) + (pi)/(12)`
    C
    `npi`
    D
    `npi pm (pi)/(12)`
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