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Two batteries of e.m.f. E(1) and E(2) an...

Two batteries of e.m.f. `E_(1)` and `E_(2)` and internal resistance `r_(1)` and `r_(2)` are connected in parallel. Determine their equivelent e.m.f.

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The correct Answer is:
`(E_(1)r_(2)+E_(2)r_(1))/(r_(1)+r_(2))`
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