Home
Class 12
PHYSICS
White light is used in a YDSE with D = 1...

White light is used in a YDSE with `D = 1 m` and `d = 0.9 mm`. Light reaching the screen at position `y = 1 mm` is passed through a prism and its spectrum is obtained. Find the missing lines in the visible region of this spectrum.

Text Solution

Verified by Experts

`Deltap=(yd)/(D) =9xx10^(-4)xx1xx10^(-3) m =900 nm`
for minima `Deltap=(2n-1)lambda//2`
`rArr lambda=(2DeltaP)/((2n-1))=(1800)/((2n-1))`
`=(1800)/(1),(1800)/(3),(1800)/(5),(1800)/(7)……..`
of these `600 nm` and `360 nm` lie in the visible range. Hence these will be missing lines in the visible spectrum.
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    RESONANCE|Exercise Exercise-1 (Part-1)|13 Videos
  • WAVE OPTICS

    RESONANCE|Exercise Exercise-1 (Part-2)|13 Videos
  • WAVE ON STRING

    RESONANCE|Exercise Exercise- 3 PART I|19 Videos

Similar Questions

Explore conceptually related problems

In a YDSE, D = 1 M, d = 1 mm, and lambda = 1//2 mm. (a) Find the distance between the first and central maxima on the screen. (b) Find the number of maxima and minima obtained on the screen.

In a YDSE, the separation between slits is 2 mm where as the distance of screen from the plane of slits is 2.5 m . Light of wavelengths in the range 200-800 nm is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at 1 mm from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.

Monochromatic light of wavelength 5000 Å is used in YDSE, with slit width, d = 1 mm , distance between screen and slits, D = 1 M . If intensites at the two slits are I_1 = 4I_0 and I_2 = I_0 , find: a. finge width beta: b. distance of 5th minima from the central maxima on the screen, c. intensity at y = (1)/(3) mm, d. distance of the 1000th maxima, and e. distance of the 5000th maxima.

White coherent light (400 nm-700 nm) is sent through the slits of a YDSE. D=0.5 mm , D=50 cm. There is a hole in the screen at a point 1.0 mm away (along the width of the fringes) from the central line. (a) Which wavelength will be absent in the light coming from the hole? (b) Which wavelength(s) will have a strong intensity?

In a YDSE, D = 1m, d = 1mm and lambda = 1//2 mm Find the no of maxima and minima obtained on the screen.

In a standard YDSE slit width is 1mm and distance of screen from the slit is 1m. If wavelength of light is 632nm and bright fringe formed at y = 1.270 mm. Find path difference for the point

Draw a ray diagram showing the dispersion through a prism when a narrow beam of white light is incident on one of its refracting surface. Also indicate the order of the colours of the spectrum obtained.

The refractive index of the mean ray in a spectrum is 1.620 . A ray of light passes through a prism whose refracting angle is 10^(@) and the dispersive power is 0.031 . What is the dispersion produced by the prism ?

Two slits are made on an opaque surface at a separation of 1 mm from each other. A screen is placed at a distance 1 m from the plane of the slits. A small hole is made on the screen at a distance 1 mm from the centre of the screen as shown in the figure. If we observe the light coming out from hole on the other side, then which wavelengths in the visible region will be absent and which will show strong presence ? Wavelength of visible light ranges from 400 nm to 700 nm.