Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` is

Options

A. `n=5, l=0, m=0, s=+1//2`
B. `n=5, l=1, m=0, s=+1//2`
C. `n=5, l=1, m=1, s=+1//2`
D. `n=6, l=0, m=0, s=+1//2`

Answer

A

Explanation

I : for `n=5, l_(min)=0, :.` Orbital angular momentum `=sqrt(l(+1)) ħ=0`. (False)
II : Outermost electronic configuration `=3s^(1)` or `3s^(2)`. :. possible atomic number `=11` or `12` (False).
III : `Mn_(25)=[Ar] 3d^(5) 4s^(2) :. 5` unpaired electrons. :. Total spin `=+- 5/2` (False).
IV : Inert gases have no unpaired electrons. :. Spin magnetic moment `=0` (True).