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Isothermal expansion from A rarr B, isoc...

Isothermal expansion from `A rarr B`, isochoric pressure increase from `B rarr C`, isobaric compression from `C rarr D`, isochoric pressure drop from `D rarr A`.

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Isobaric expansion from A rarr B , isochoric pressure drop from B rarr C , isothermal compression C rarr A .

Isothermal expansion from state A to B , isochoric pressure increment from B to C , isothermal contraction from C to D , isobaric contraction from D rarr A .

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  • 0.2 moles of an ideal gas is taken round the cycle ABC as shown in the figure. The path B rarr C is an adiabatic process A rarr B is an isochoric process and C rarr A is an isobaric process. The temperature at A and B are T_(A) 300 K and T_(B) = 500 k and pressure at A is 1 atm and volume at A is 4.91. The volume at C is (given : gamma = (C_(P))/(C_(V)) = (5)/(3), R = 8.205 xx 10^(-2) L "atm mol"^(-1) K^(-1), ((3)/(2))^(2//5) = 0.81 )

    A
    6.9 L
    B
    6.6 L
    C
    5.5 L
    D
    5.8 L

  • A fixed mass of gas is taken through a process A rarr B rarr C rarrA . Here A rarr B is isobaric, B rarr C is adiabatic and C rarr A is isothermal. Find pressure at C .

    A
    `(10^(5))/( 64) N //m^(2)`
    B
    `(10^(5))/( 32) N //m^(2)`
    C
    `(10^(5))/( 12) N //m^(2)`
    D
    `(10^(5))/( 6) N //m^(2)`

  • n mole a perfect gas undergoes a cyclic process ABCA (see figure) consisting of the following processes. A to B : Isothermal expansion at temperature T so that the volume is doubled from V_1 to V_2 = 2V_1 and pressure changes from P_1 to P_2 B to C : Isobaric compression at pressure P_2 to initial volume V_1 C to A : Isochoric change leading to change of pressure from P_2 to P_1 . Total work done in the complete cycle ABCA is :

    A
    0
    B
    `nRT (ln2 + 1/2)`
    C
    `nRTln2`
    D
    `nRT (ln2 - 1/2)`

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    100 mol of an ideal monatomic gas undergoes the following thermodynamic process as shown in the figure ( P-V or Pressure-Volume plots are shown) A rarr B: Isothermal expansion B rightarrow C Adiabatic expansion C rarr D: Isobaric compression D rarr A: Isochoric process ,br> The heat transfer along the process A B is 9 xx 10^(4) J . The net work done by the gas during the cycle is k xx 10^(4) J . Find k , (Take R=8 (~J) . (K)^(-1) (~mol)^(-1) ) '(##CEN_KSR_PHY_JEE_C15_E01_030_Q18##)'

    The process which occurs in going from B rarr C is

    On mole of a monoatomic ideal gas is taken through the cycle shown in figure . A rarr B : Adiabatic expansion " " BrarrC : Cooling at constant volume CrarrD : Adiabatic compression " " D rarr A : Heating at constant volume The pressure and temperature at A , B , etc, are denoted by P_(A) , T_(A) , P_(B) , T_(B) etc., respectively . Given that T_(A) = 1000K, P_(B) = ((2)/(3))P_(A)"and"P_(C) = ((1)/(3))P_(A) . Calculate the following quantities: (i) The work done by the gas in the processs A rarr B (ii) The heat lost by the gas in the process B rarr C (iii) The temperature T_(D). ("Given" : ((2)/(3))^(2//5) = 0.85 )

    For the reaction : A + 2B rarr C + D , the expression of rate of reaction will be :

    For the reaction, A+2B rarr C , the differential from of the rate law is:

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