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The molar heat capacity , C(v) of helium...

The molar heat capacity , `C_(v)` of helium gas is `3//2R` and is independent of temperature. For hydrogen gas, `C_(v)` approaches `3//2R` at very low temperature, equal `5//2R` at moderate temperature and is higher than `5//2 R` at high temperatures. Give a reason for the temperature dependence of `C_(v)` in case of hydrogen, in not more than two or three sentences.

Text Solution

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The correct Answer is:
Hydrogen is diatomic so at high temperature rational and vibrational motion also counts.

Helium `(He)` gas is monoatomic and it has three translational degree of freedom. Hence, contribution of each transiational degree of freeedom towards `C_(v)` being `R//2`, so the total contribution towards `C_(v)=3xxR//2`. Hydrogen molecule is diatomic. At low temperature, rotational and vibrational contribution for `H_(2)` are zero. So, `C_(v)` for `H_(2)` at low temperature continues to be `3R//2`. At moderate temperature, rotational contribution `(=2xxR//2)` also becomes dominant and hence total contribution towards `C_(v)=(3R)/(2)+R=(5R)/(2)`. At even high temperature, vibrational contribution `(=1xxR)` also becomes significant. Hence total contibution towards `C_(v)=(3R)/(2)+R+R=(7R)/(2)`
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Knowledge Check

  • The molar heat capacity, C_(v) of helium gas is 3//2 R and is independent of temperature. For hydrogen gas, C_(v) approaches 3//2 R at a very low temperature, equals 5//2 R at moderate temperature and is higher than 5//2 R at high temperature. Choose the correct reason for the temperature dependence of C_(v) in case of hydrogen :

    A
    Hydrogen is diatomic so at high temperature rotational and vibrational motion also counts
    B
    Hydrogen is monoatomic so at high temperature rotational and vibrational motion also counts
    C
    Hydrogen is diatomic so at high temperature rotational and vibrational motion are not counted
    D
    can’t be defined
  • The molar heat capacity at constant pressure of nitrogen gas at STP is nearly 3.5 R . Now when the temperature is increased, it gradually increases and approaches 4.5 R . The most approprite reason for this behaviour is that at high temperatures

    A
    nitrogen does not behave as an ideal gas
    B
    nitrogen molecules dissociate in atoms
    C
    the molecules collides more frequently
    D
    molecules vibration gradually beome effective
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