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The enthalpies of combustion of carbon a...

The enthalpies of combustion of carbon and carbon monoxide are `-393.5` and `-283` kJ `mol^(-1)` respectively. The enthaly of formation of carbon monoxide per mole is :

A

`110.5 kJ`

B

`676.5 KJ`

C

`-676.5 KJ`

D

`-110.5 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`C(s) + O_(2)(g) rarr CO_(2) , DeltaH = -393.5 kJ mol^(-1) " ""…."(i)`
`CO(g) + (1)/(2)O_(2)(g) rarr CO_(2)(g), DeltaH = - 283 "KJmol"^(-1)" ""…."(ii)`
On subraction equation (2) from equation (1) , we get `C(s) + O_(2)(g) rarr CO(g), DeltaH = -110.5 "KJ mol"^(-1).`
The enthalpy of formation of carbon monoxide per mole `=-110.5 "KJ mol"^(-1)`
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Knowledge Check

  • The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol^(-1) respectively. The enthalpy of formation of carbon monoxide per mole is

    A
    110.5 kJ
    B
    676.5 kJ
    C
    `-676.5 kJ`
    D
    `-110.5 kJ`

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    C
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