Home
Class 12
CHEMISTRY
Heat of combustion of ethanol at constan...

Heat of combustion of ethanol at constant pressure and at temperature T K(=298 K) is found to be -qJ `"mol"^(-1)`. Hence , heat of combustion (in J `"mol"^(-1)`) of ehtanol at the same temperature at constant volume will be:

A

RT-q

B

`-(q+RT)`

C

q-RT

D

q+RT

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 3H_(2)O(r)`
`Deltan_(3)=2-3=-1`
so `DeltaU=DeltaH-Deltan_(g)RT`
`=-q+RT`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 part-2 Advanced level Solutions|27 Videos

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 part-III Advanced level Solutions (STAGE-I)|6 Videos

  • THERMODYNAMICS

    RESONANCE|Exercise exercise-3 Part:(I)|23 Videos

  • TEST SERIES

    RESONANCE|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

The heat of combustion of gaseous methane (CH_(4)) at constant volume is measured in bomb calorimeter at 298K is found to be -885.4kjmol^(-1) . Find the value of enthalpy change at the same temperature.

The heat of combustion of H_(2)(g) at constant pressure and 300k is -280kJ mol^(-1) . What will be the heat of combustion at constant volume and at 300K ?

Knowledge Check

  • Heat of combustion of ethanol at constant pressue and at temperature TK(=298K) is found to be -qJmal^(-1) . Hence, heat of combustion (in Jmol^(-1) ) of ethanol at the same temperature at constant volume will be:

    A
    `RT-q`
    B
    `-(q+RT)`
    C
    `q-RT`
    D
    `q+RT`

  • Heat of combustion of ethanol at constant pressure and at temperature TK is found to be -q J" mol"^(-1) . Hence, heat of combustion (in J mol^(-1) ) of ethanol at the same temperature and at constant volume will be :

    A
    `RT-q`
    B
    `-(q+RT)`
    C
    `q-RT`
    D
    `q+RT`

  • The combustion of benzene (1) gives CO_(2)(g) and H_(2)O(1) . Given that heat of combustion of benzene at constant volume is .^(-)3263.9 kJ mol^(-1) " at "25^(@)C , heat of combustion (in kJ mol^(-1) ) of benzene at constant pressure will be (R=8.314 JK^(-1) mol^(-1))

    A
    `- 452.46`
    B
    3260
    C
    `- 3267.6`
    D
    4152.6

    • Similar Questions

    Explore conceptually related problems

    The heat of combustion of gaseous methan (CH_(4)) at constant volume is measured in a bomb calorimeter at 298 K and is found to be -885.4 kJ mol^(-1) .Find the value of enthalpy change.

    The combustion of benzene (1) gives CO_(2) (g) and H_(2)O (l). Given that heat of combustion of benzene at constant volume is -3263.9kJ"mol"^(-1) at 25^(@)C , heat of combustion (in kJ"mol^(-1) ) of benzene at constant pressure will be ( R=8.314JK^(-1)"mol"^(-1) )

    The activation energy for a reaction at temperature T K was found to be 2.303" RT J mol"^(-1) . The ratio of the rate constant to Arrhenius factor is

    The combustion of benzene (l) gives CO_(2)(g) and H_(2)O(l) . Given that heat of combustion of benzene at constant volume is –3263.9 kJ mol^(–1) at 25^(@)C , heat of combustion (in kJ mol^(–1) ) of benzene at constant pressure will be (R = 8.314 JK–1 mol–1)

    The combustion of benzene (l) gives CO_(2)(g) and H_(2)O(l) .Given that heat of combustion of benzene at constant volume is -3263.9 kJ mol^(-1) at 25^(@)C , heat of combustion (in kJ mol^(-1) ) of benzene at constant pressure will be (R = 8.314 JK^(-1) mol^(-1) ).

    Home
    Profile