Oxidation product of 1,2-cyclopentane-diol with `HlO_(4)` is

Options

A.
B.
C.
D. none is correct

Answer

To determine the oxidation product of 1,2-cyclopentane-diol when reacted with periodic acid (HIO4), we can follow these steps:

### Step 1: Understand the Structure of 1,2-Cyclopentane-Diol
1,2-Cyclopentane-diol is a cyclic compound with a five-membered ring (cyclopentane) and two hydroxyl (OH) groups located on adjacent carbon atoms (1 and 2). The structure can be represented as follows:

```
OH
|
C1-C2
/ \
C5 C3
\ /
C4
```

### Step 2: Identify the Reaction with HIO4
Periodic acid (HIO4) is known to oxidize vicinal diols (diols with hydroxyl groups on adjacent carbons) by cleaving the C-C bond between the two carbons that bear the hydroxyl groups. This reaction typically results in the formation of carbonyl compounds (aldehydes or ketones).

### Step 3: Apply the Reaction Mechanism
In the case of 1,2-cyclopentane-diol, the two hydroxyl groups on carbons 1 and 2 are adjacent. When HIO4 reacts with this diol, it will cleave the bond between C1 and C2, resulting in the formation of two carbonyl groups.

### Step 4: Determine the Products
After the cleavage, the resulting products will be:
- A carbonyl compound (aldehyde or ketone) from the cleavage of the C-C bond.
- The remaining part of the ring will also be affected, leading to the formation of a new structure.

The final product will be a compound with a double bond to oxygen (C=O) at the positions where the hydroxyl groups were originally located.

### Step 5: Write the Final Structure
The final product can be represented as follows:

```
O
||
C1-C2
/ \
C5 C3
\ /
C4
```

This structure indicates that the original cyclopentane ring has been transformed, and we have a carbonyl group at the position where the hydroxyl groups were located.

### Conclusion
The oxidation product of 1,2-cyclopentane-diol with HIO4 is a compound with two carbonyl groups formed from the cleavage of the vicinal diols.

---