Home
Class 12
MATHS
Let f be a non-negative function defined...

Let f be a non-negative function defined on the interval .[0,1].If `int_0^x sqrt[1-(f'(t))^2].dt`=`int_0^x f(t).dt`, `0<=x<=1` and f(0)=0,then

A

`f(1/2)lt 1/2` and `f(1/3)gt 1/3`

B

`f(1/2)gt 1/2` and `f(1/3)gt1/3`

C

`f(1/2)lt1/2` and `f(1/3)lt1/3`

D

`f(1/2)gt 1/2` and `f(1/3)lt 1/3`

Text Solution

Verified by Experts

The correct Answer is:
C

`f'=+-sqrt(1-f^(2))`
or `f(x)=sinx `or `f'(x)=-sinx` (not possible)
`:. f(x)=sinx`
Also `xgtsinxAAxgt0`
Promotional Banner

Topper's Solved these Questions

  • DEFINITE INTEGRATION

    CENGAGE|Exercise JEE Main Previous Year|12 Videos
  • CURVE TRACING

    CENGAGE|Exercise Exercise|24 Videos
  • DETERMINANT

    CENGAGE|Exercise Multiple Correct Answer|5 Videos

Similar Questions

Explore conceptually related problems

Let f be a non-negative function defined on the interval [0,1] . If int_0^xsqrt(1-(f\'(t))^2)dt=int_0^xf(t)dt, 0lexle1 and f(0)=0 , then (A) f(1/2)lt1/2 and f(1/3)gt1/3 (B) f(1/2)gt1/2 and f(1/3)gt1/3 (C) f(1/2)lt1/2 and f(1/3)lt1/3 (D) f(1/2)gt1/2 and f(1/3)lt1/3

Let f be a non-negative function defined on the interval [0,1]dot If int_0^xsqrt(1-(f^(prime)(t))^2)dt=int_0^xf(t)dt ,0lt=xlt=1,a n df(0)=0,t h e n (A)f(1/2) 1/3 (B)f(1/2)>1/2a n df(1/3)>1/3 (C)f(1/2) 1/2a n df(1/3)<1/3

Let f be a non-negative function in [0, 1] and twice differentiate in (0, 1). If int_0^x sqrt(1-(f'(t))^(2))dt=int_0^x f(t)dt , 0 lexle1 and f(0)=0 then the value of lim_(x to0)int_0^xf(t)/x^2 dt is

Let f be a function defined on the interval [0,2pi] such that int_(0)^(x)(f^(')(t)-sin2t)dt=int_(x)^(0)f(t)tantdt and f(0)=1 . Then the maximum value of f(x) is…………………..

Let f(x) be a non constant function such that int _(0) ^(x) (f (t))^(3) dt = (1)/(x ^(2))(int _(0) ^(x) (f(t)dt ) ) ^(3) AA x in R- {0} If f(1)=1 then f((1)/(2))=

Let f(x) be a continuous function which takes positive values for xge0 and satisfy int_(0)^(x)f(t)dt=x sqrt(f(x)) with f(1)=1/2 . Then

If int_(0)^(1) f(t)dt=x^2+int_(0)^(1) t^2f(t)dt , then f'(1/2)is

CENGAGE-DEFINITE INTEGRATION -JEE Advanced Previous Year
  1. Let f be a non-negative function defined on the interval .[0,1].If int...

    Text Solution

    |

  2. The value of int0^1(x^4(1-x)^4)/(1+x^2)\ dx is

    Text Solution

    |

  3. Let f be a real-valued function defined on the inverval (-1,1) such th...

    Text Solution

    |

  4. The valued of int(sqrt(In2))^(sqrt(In3)) (x sinx^(2))/(sinx^(2)+sin(In...

    Text Solution

    |

  5. Let f:[-1,2]vec[0,oo) be a continuous function such that f(x)=f(1-x)fo...

    Text Solution

    |

  6. Let f:[1/2,1]vecR (the set of all real numbers) be a positive, non-con...

    Text Solution

    |

  7. Let f:[0,2]vecR be a function which is continuous on [0,2] and is diff...

    Text Solution

    |

  8. int((pi)/4)^((pi)/2)(2cosecx)^17 dx

    Text Solution

    |

  9. Let f prime(x)=(192x^3)/(2+sin^4 pix) for all x in RR with f(1/2)=0. I...

    Text Solution

    |

  10. Evaluate: int(-pi//2)^(pi//2)(cosx)/(1+e^x)dx

    Text Solution

    |

  11. If In=int(-pi)^(pi) \ (sinnx)/((1+pi^x) \ sinx) \ dx, n=0,1,2,...... t...

    Text Solution

    |

  12. Let f be a real-valued function defined on interval (0,oo),by f(x)=lnx...

    Text Solution

    |

  13. Let S be the area of the region enclosed by y=e^-x^2,y=0,x=0,a n dx=1....

    Text Solution

    |

  14. Find a for which lim(n->oo) (1^a+2^a+3^a+...+n^a)/((n+1)^(a-1)[(na+1)+...

    Text Solution

    |

  15. Let f:[a,b]to[1,oo) be a continuous function and let g:RtoR be defined...

    Text Solution

    |

  16. Let f:(0,oo) in R be given f(x)=overset(x)underset(1//x)int e^-(t+(1...

    Text Solution

    |

  17. The option(s) with the values of aa n dL that satisfy the following eq...

    Text Solution

    |

  18. Let f(x)=7tan^8x+7tan^6x-3tan^4x-3tan^4x-3tan^2x for all x in (-pi/2,...

    Text Solution

    |

  19. Let f(x)=lim(n->oo)((n^n(x+n)(x+n/2)....(x+n/n))/(n!(x^2+n^2)(x^2+n^2/...

    Text Solution

    |

  20. Let f: Rvec(0,1) be a continuous function. Then, which of the followin...

    Text Solution

    |