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The period of revolution of an electron ...

The period of revolution of an electron in the ground state of hydrogen atom is T. The period of revolution of the electron in the first excited state is

A

2 T

B

4 T

C

6 T

D

8 T

Text Solution

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The correct Answer is:
D
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Calculate the energy of the electron in the ground state of the hydrogen atom.

The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.60 xx 10^(-16) second. The time period of revolution of the electron in its first excited state in a Li^(++) ion is:

Knowledge Check

  • The time period of revolution of electron in its ground state orbit in a hydrogen atom is 1.60xx 10 ^(-16)s. The time period of revolution of the electron in its second excited state in a He ^(+) ion is:

    A
    `1.08xx10 ^(-15)s`
    B
    `1.30 xx10^(-15)s`
    C
    `2.30 xx10^(-14)s`
    D
    `2.08xx 10^(-14)s`

  • The time period of the electron in the ground state of hydrogen atom is two times the times period of the electon in the first excited state of a certain hydrongen like atom (Atomic number Z). The value of Z is

    A
    `2`
    B
    `3`
    C
    `4`
    D
    None of these

  • The total energy of eletcron in the ground state of hydrogen atom is -13.6 eV . The kinetic enegry of an electron in the first excited state is

    A
    `3.4 eV`
    B
    `6.8 eV`
    C
    `13.6 eV`
    D
    `1.7 eV`

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    In Bohr's model of the hydrogen atom the ratio between the period of revolution of an electron in the orbit of n=1 to the period of the revolution of the electron in the orbit n=2 is :-

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