The most acidic oxide among the following is

Options

A. `SO_(3)`
B. `P_(2) O_(5)`
C. `Cl_(2) O_(7)`
D. `SiO_(2)`

Answer

To determine the most acidic oxide among the given options (SO3, P2O5, Cl2O7, SiO2), we will analyze the oxidation states of the central atoms in each oxide. The oxide with the highest oxidation state will generally exhibit the most acidic character.

### Step-by-Step Solution:

1. **Identify the Oxides and Their Central Atoms:**
- SO3: Central atom is Sulfur (S)
- P2O5: Central atom is Phosphorus (P)
- Cl2O7: Central atom is Chlorine (Cl)
- SiO2: Central atom is Silicon (Si)

2. **Calculate the Oxidation State for Each Oxide:**
- **For SO3:**
- Let the oxidation state of Sulfur be \( x \).
- The equation is: \( x + (-2) \times 3 = 0 \)
- Solving gives: \( x - 6 = 0 \) → \( x = +6 \)

- **For P2O5:**
- Let the oxidation state of Phosphorus be \( x \).
- The equation is: \( 2x + (-2) \times 5 = 0 \)
- Solving gives: \( 2x - 10 = 0 \) → \( 2x = 10 \) → \( x = +5 \)

- **For Cl2O7:**
- Let the oxidation state of Chlorine be \( x \).
- The equation is: \( 2x + (-2) \times 7 = 0 \)
- Solving gives: \( 2x - 14 = 0 \) → \( 2x = 14 \) → \( x = +7 \)

- **For SiO2:**
- Let the oxidation state of Silicon be \( x \).
- The equation is: \( x + (-2) \times 2 = 0 \)
- Solving gives: \( x - 4 = 0 \) → \( x = +4 \)

3. **Compare the Oxidation States:**
- SO3: +6
- P2O5: +5
- Cl2O7: +7
- SiO2: +4

4. **Determine the Most Acidic Oxide:**
- The oxide with the highest oxidation state is Cl2O7, which has an oxidation state of +7.

### Conclusion:
The most acidic oxide among the given options is **Cl2O7**.