Home
Class 11
CHEMISTRY
The reaction M^(n+)MnO(4)^(-)toMO(3)^(-)...

The reaction `M^(n+)MnO_(4)^(-)toMO_(3)^(-)+Mn^(2+)+`occurs in and acid medium . In the reaction , If 1 mol of `MnO_(4)^(-1)` oxidised 1.67 mol `M^(n+)`,then calculate the value of n.

Text Solution

Verified by Experts

Oxidation reactions:
`[M^(n+)+3H_(2)OtoMO_(3)^(-)+6H^(+)+(5-n)e]xx5`
Reduction reaction : `underline([MnO_(4)^(-)+8H^(+)+5etoMn^(2+)+4H_(2)O]xx(5-n))`
Net reaction :
`5M^(n+)MnO_(4)^(-)+(4n-5)H_(2)Oto(5-n)Mn^(2+)+5MO_(3)^(-)+(8n-10)`
Therefore ,(5-n) mol of `MnO_(4)^(-)-=5mol of Mn^(n+)`
or,1 mol of `MnO_(4)^(-)=((5)/(5-n))mol of Mn^(n+)`
Given : 1 mol of `MnO_(4)^(-)` oxidises 1.67 mol of `M^(n+)`
`therfore(5)/(5-n)=1.67ornN=2`
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|4 Videos

  • REDOX REACTIONS

    CHHAYA PUBLICATION|Exercise EXERCISE (ADDITIONAL QUESTION )|13 Videos

  • CLASSIFICATION OF ELEMENTS & PERIODICITY IN PROPERTIES

    CHHAYA PUBLICATION|Exercise PRACTICE SET|12 Videos

  • s-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|16 Videos

Similar Questions

Explore conceptually related problems

M^(x+)+MNO_(4)^(-)toMO_(3)^(-)+Mn^(2+)(1)/(2)O_(2) : If the 1 mol of MnO_(4)^(-) oxidised 2.5 mol of M^(x+) ,then the value of x is -

MnO_(4) reacts with A^(x+) to from AO_(3)^(-),Mn^(2+)and O_(2) .One mole of MnO_(4)^(-) oxidises 1.25 mole of A^(x+) to AO_(3)^(-) , what is the value of x?

How much charge is required for the following reductions : 1 mol of MnO_(4)^(-) to Mn^(2+) ?

The disproprotionation of 1 mol of MnO_(4-)^(2-) ions is a neutral aqueous solution results in-

In a neutral medium, 1 mol of MnO_(4)^(2-) ion undergoes disproportionation to form -

In a reaction 1.0 mol of MnSO_4 was completely converted to 1.0 mol of MnO_4^- Calculate the equivalent mass of MnO_4^- [Mn = 54.94]

How many coulombs of electricity will be required to reduce 1 mol of MnO_(4)^(-)" of "Mn^(2+) .

n-factor of Ba (MnO_4)_2 in acidic medium is :

For a reaction involving 1 mol of Zn and 1 mol of H_(2)SO_(4) in a bomb calorimeter-

MnO_(4)^(2-) undergoes disproportionation reaction in acidic medium but MnO_(4)^(-) does not .Give reason.

Knowledge Check

  • M^(x+)+MNO_(4)^(-)toMO_(3)^(-)+Mn^(2+)(1)/(2)O_(2) : If the 1 mol of MnO_(4)^(-) oxidised 2.5 mol of M^(x+) ,then the value of x is -

    A
    5
    B
    3
    C
    4
    D
    1

  • The disproprotionation of 1 mol of MnO_(4-)^(2-) ions is a neutral aqueous solution results in-

    A
    1/3 mol of `MnO_(4)^(-)`
    B
    2/3 mol of `MnO_(2)`
    C
    `2/3 mol of MnO_(4)^(-)`
    D
    1/3 mol of `MnO_(2)`

  • In a neutral medium, 1 mol of MnO_(4)^(2-) ion undergoes disproportionation to form -

    A
    `(2)/(3)` mol `MnO_(4)^(-)` and `(1)/(3)` mol `MnO_(2)`
    B
    `(1)/(3)` mol `MnO_(4)^(-)` and `(2)/(3)` mol `MnO_(2)`
    C
    `(1)/(3)` mol `Mn_(2)O_(7)` and `(1)/(3)` mol `MnO_(2)`
    D
    `(2)/(3)` mol `Mn_(2)O_(7)` and `(1)/(3)` mol `MnO_(2)`