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The current voltage relation of diode is...

The current voltage relation of diode is given by `I=(e^(1000(V)/(T))-1)`mA where the applied voltage V is in volt and the temperature T is in kelvin. If a student makes an error `pm 0.01` V in voltage while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

A

0.2 mA

B

0.02 mA

C

0.5 mA

D

0.05 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`5=e^(1000(V)/(T))-1" ""or" " "e^(1000(V)/(T))=6`
Again, `I=e^(1000(V)/(T))-1`
`:. " " (dI)/(dV)=e^((1000V)/(T))(1000)/(T) " ""or",dI =(1000)/(T)e^((1000V)/(T))dV`
Using equation (1)
`DeltaI=(1000)/(T)xx6xx0.01=(60)/(T)`
`=(60)/(300)=0.2` mA
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Knowledge Check

  • The current voltage relation of diode is given by I= (e^(1000v/T) -1) mA , when the applied voltage V is in volts and the temperature T is in degree Kelvin.If a student makes an error measuring +-0.01 V while measuring the current of 5 mA at 300 K what will be the error in the value of current in mA

    A
    0.2 mA
    B
    0.02 mA
    C
    0.5 mA
    D
    0.05 mA

  • Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applies across it. If the percentage errors in the measurement of the current and voltage difference are 3% each then in the value of resistance of the wire is

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    `6%`
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    zero
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    `1%`
    D
    `3%`

  • A voltage V_0sinomegat is applied across a series combination of resistance R and inductor L. The peak value of the current in the circuit is

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