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A student performing an experiment of measuring the thickness of a slab with a vernier calliper whose 50 divisions of the vernier scale are equal to 49 divisions of the main scale. He noted that zero of the vernier scale is between 7.00 cm and 7.05 cm mark of the main scale and 23rd division of the vernier scale exactly coincides with the main scale. The measured value of the thickness of the given slab using the calliper will be

A

7.73 m

B

7.23 cm

C

7.023 cm

D

7.073 cm

Text Solution

Verified by Experts

The correct Answer is:
C

Smallest division of main scale
a = 7.05 -7.00 = 0.05 cm
`:.` Smallest division of vernier scale b `= 0.05 xx(49)/(50)` cm
`:.` Vernierconstant = a-b =0.05 `(1-(49)/(50))=0.05 xx(1)/(50)`
=0.001 cm
`:.` Thickness of the slab = `7.00 +23 xx 0.001 = 7.023 ` cm
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Knowledge Check

  • In case of a metal scale

    A
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    B
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    C
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    D
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    D
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    C
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