Home
Class 11
PHYSICS
A projectile is launched from the ground...

A projectile is launched from the ground and it returns to the ground level. The horizontal range of the projectile is R= 175 m . If the horizontal component of the projectile's velocity at any instant is `25 m *s^(-1)` , then determine the time of flight of the projectile.

Text Solution

Verified by Experts

The correct Answer is:
7
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (WBCHSE)|19 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (WBJEE)|6 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Comprehension type)|10 Videos

  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

A particle is projected from . the ground at an angle theta with the horizontal with an initial speed of ‘u’. Find the time after which velocity vector, of the projectile is perpendicular to the initial velocity

The velocity of a projectile is 15m/s .At what angle to the horizontal should it be projected so that it cover maximum horizontal distance?

Knowledge Check

  • The times of flight of two projectiles are t_1 and t_2 . If R be the horizontal range of each of them, then

    A
    `t_1t_2 propR`
    B
    `t_1t_2 prop R^2`
    C
    `t_1t_2 prop R^3`
    D
    `t_1t_2 prop R^(1/2)`

  • A projectile is fired from level ground at an angle theta above the the horizontal. The elevation angle phi of the highest point as seen from the launch point is related to theta by the relation :

    A
    `tan phi = 1/4 tan theta`
    B
    `tan phi = tan theta`
    C
    `tan phi = 1/2 tan theta`
    D
    `tan phi = 2 tan theta`

  • A particle is projected from the surface of the earth with a speed of 20 m* s^(-1) at an angle 30^@ with the horizontal . The time of flight of that particle is

    A
    3 s
    B
    4 s
    C
    2 s
    D
    1 s

    • Similar Questions

    Explore conceptually related problems

    What is a projectile ? Obtain an expression for: maximum height , time of flight and the horizontal range when a projectile is fired at an angle theta with the horizontal.

    A projectile is fired from the surface of the earth with a velocity of 5m *s^(-1) and angle theta with the horizontal . Another projectile fired from another planet with a velocity of 3 m*s^(-1) at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in m*s^(-2) ) (given g=9.8 m*s^(-2) )

    A projectile is fired from the surface of the earth with a velocity of 5 ms^-1 and angle theta with the horizontal. Another projectile fired from another planet with a velocity of 3 ms^-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in ms^-2 ) is: (given g = 9.8 ms^-2 )

    Statement I: During the flight of a projectile, the horizontal component of its velocity remains uniform . Statement II: The vertical component of the velocity of a projectile becomes zero at the highest point of its path.

    A projectile is fired with a velocity u at right angle to the slope which is inclined at an angle theta with the horizontal. The expression for the range along the inclined plane is

    Home
    Profile