Home
Class 11
PHYSICS
Consider three vectors vecA =hati+hatj-...

Consider three vectors `vecA =hati+hatj-2hatk,vecB=hati-hatj+hatk and vecC =2hati-3hatj+4hatk` . A vector `vecX` of the form `alpha vecA+betavecB(alpha and beta ` are numbers ) is perpendicular to `vecC` . The ratio of `alpha and beta` is

A

`1:1`

B

`2:1`

C

`-1:1`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
A

`(alpha vecA+betavecB)*vecC=0`
or, `2(alpha+beta)-3(alpha-beta)+4(beta-2alpha)=0`
or, `-9alpha+9beta=0 or, alpha:beta =1:1`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (AIPMT)|3 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (NEET)|4 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (WBCHSE)|19 Videos
  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos
  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

Find the sum of the vectors veca=hati-2hatj+hatk,vecb=-2hati+4hatj+5hatkandvecc=hati-6hatj-7hatk .

If veca=2hati+3hatj+hatk, vecb=hati-2hatj+hatk and vecc=-3hati+hatj+2hatk , then [veca vecb vecc]=

Knowledge Check

  • Consider three vectors vecA = hati + hatj - hatk, vecB = hati - hatj + veck and vecC = 2hati - 3hatj + 4hatk A vector vecx of the form alphavecA + betavecB (alpha and beta are umber) is perpendicular to vecC . The ratio of alpha:beta

    A
    1:1
    B
    2:1
    C
    -1:2
    D
    3:2
  • If vecA= 5hati+6hatj+3hatk and vecB=6hati-2hatj-6hatk , then

    A
    `vecA and vecB` are perpendicular
    B
    `vecA xxvecB=vecBxxvecA`
    C
    `vecA and vecB` have the same magnitude
    D
    `vecA*vecB=0`
  • If veca=hati+3hatj+hatk, vecb=2hati-hatj-hatk and vec c=m hati+7hatj+3hatk are coplanar, then the value of m is -

    A
    m = -2
    B
    m = 0
    C
    m = 1
    D
    m = 3
  • Similar Questions

    Explore conceptually related problems

    Show that the vectors veca=3hati-2hatj+hatk, vecb=hati-3hatj+5hatk and vecc=2hati+hatj-4hatk form a right angled triangle.

    Find the angle between the two vectors vecA = hati + 2hatj + 3hatk and vecB = 2hati+ hatj + 4hatk .

    vecA =2hati+3hatj+4hatk and vecB=hati-hatj+hatk are two vectors. Find vecAxxvecB .

    Find the angle between the two vectors vecA =hati-2hatj+3hatk and vecB=2hati+hatj+3hatk .

    vecA=2hati+hatj, vecB=2hatj-hatk and vecC=6hati-2hatk . Value of vecA-2vecB+3vecc would be