Home
Class 11
PHYSICS
A farmer goes 500 m due north, 400 m due...

A farmer goes 500 m due north, 400 m due east and 200m due south to reach his field. He takes 20 min to reach the field .
How much distance has he to walk to reach the field ?

A

900 m

B

1100 m

C

1300 m

D

700 m

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Integer answer type)|2 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (WBCHSE)|19 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Multiple correct answers type)|11 Videos
  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos
  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

A man goes 24 m due west and then 7 m due north. How far is he from the starting point?

A boat has to cross a river. It crosses the river by making an angle of 60^(@) with the bank of the river due to the stream of the river and travels a distance of 600m to reach the another side of the river. What is the width of the river?

Knowledge Check

  • A farmer goes 500 m due north, 400 m due east and 200m due south to reach his field. He takes 20 min to reach the field . What is the displacement from his house to the field ?

    A
    550 m
    B
    700 m
    C
    500 m
    D
    714 m
  • A farmer goes 500 m due north, 400 m due east and 200m due south to reach his field. He takes 20 min to reach the field . What is the average speed of the farmer during the walk?

    A
    `35 m* min^(-1)`
    B
    `63 m*min^(-1)`
    C
    `55 m*min^(-1)`
    D
    `65 m*min^(-1)`
  • A farmer goes 500 m due north, 400 m due east and 200m due south to reach his field. He takes 20 min to reach the field . What is the average velocity of the farmer during the walk ?

    A
    `27 m*min^(-1)`
    B
    `30 m*min^(-1)`
    C
    `35 m*min^(-1)`
    D
    `25 m*min^(-1)`
  • Similar Questions

    Explore conceptually related problems

    A string of mass 2.50kg is under a tension of 200N. The length of the stretched string is 20.0m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end?

    A man swims across the river which flows with a velocity of 3 km/h due east.if the velocity of man relative to water is 4 km/h due north, then How long does he take to across the river if the river is 1 km wide?

    A string of length 40 cm and weighing 10 g is attached to a spring at one end and to a fixed wall at the other end. The spring has a spring constant of 160 N/m and is stretched by 1.0 cm. If a wave pulse is produced on the string near the wall, how much time will it take to reach the spring ?

    Answer the following: (a) The top of the atmosphere is at about 400 kV with respect to the surface of the earth, corresponding to an electric field that decreases with altitude. Near the surface of the earth, the field is about 100 Vm^(-1) . Why then do we not get an electric shock as we step out of our house into the open? (Assume the house to be a steel cage so there is no field inside!) (b) A man fixes outside his house one evening a two metre high insulating slab carrying on its top a large aluminium sheet of area 1m^(2) . Will he get an electric shock if he touches the metal sheet next morning (c) The discharging current in the atmosphere due to the small conductivity of air is known to be 1800 A on an average over the globe. Why then does the atmosphere not discharge itself completely in due course and become electrically neutral? In other words, what keeps the atmosphere charged? (d) What are the forms of energy into which the electrical energy of the atmosphere is dissipated during a lightning? (Hint: The earth has an electric field of about 100 Vm^(-1) at its surface in the downward direction, corresponding to a surface charge density = –10^(–9) Cm^(–2) . Due to the slight conductivity of the atmosphere up to about 50 km (beyond which it is good conductor), about + 1800 C is pumped every second into the earth as a whole. The earth, however, does not get discharged since thunderstorms and lightning occurring continually all over the globe pump an equal amount of negative charge onthe earth.)

    In a Tsunami, the entire ocean, participate in the wave motion, For such waves, the wave speed is given by v= sqrt(gh) where g is the acceleration due to gravity and h=3.0 km is the depth of the ocean surface. A Tsunami has been detected at a point 250 km from the shore. How much time would it take to reach the shore?