Find the equation of the locus of a poin...

Find the equation of the locus of a point, which forms a triangle of area 2 with the points A(1, 1) and B (-2, 3).

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The set of all points that forms a triangle of area 15 sq units with the points (1, -2) and (-5, 3) lies on

`5x+6y+23=0`

`(5x+6y-23) (5x+6y+37)=0`

`25 x^(2)+36 y^(2)+24 x-30 y-227 =0`

`5x+6y-37=0`

The set of all points that forms a triangle of area 15 sq. Units with the points (1,-2) and (-5,3) lies on ,

5x+6y+23=0

(5x+6y-23)(5x+6y+37)=0

`25x^2+36y^2+24x-30y-227=0`

5x+6y-37=0

The equation to the locus of points which are equal distance from the points (1,-3,4),(1,3,4) is

xy=0

y=0

z=0

x=0