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(a) Explain the action of Cone. HCl on K...

(a) Explain the action of Cone. HCl on `KMnO_4` crystals
(b) Write the structure of perchloric acid.

Text Solution

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(a) When `KMnO_(4)` is treated with cone. HC1 chlorine is liberated.
`2KMnO_(4) +16HCI —rarr 2KCl + 2MnCI_(2) + 8H_(2)O + 5Cl_(2)`
(b)
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