Let `f(x)=x sin pix`, `x gt 0` Then for all natural numbers n, f`(x) vanishes at
A
`"a unique point in the interval "(n,n+(1)/(2))`
B
`"a unique point in the interval "(n+(1)/(2),n+1)`
C
`"a unique point in the interval "(n,n+1)`
D
`"two points in the interval "(n,n+1)`
Text Solution
Verified by Experts
`"We have "f'(x)=sin pix+pi x cos pi x=0` `"or "tan pi x=-pix` The graph of `y=tan pi x and y= - pi x` is as shown in the following figure. Therefore, `tan pix=-pix` From the graph `x in (n+(1)/(2),n+1)or (n, n+1)`
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