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If the energy of a photon corresponding ...

If the energy of a photon corresponding to a wavelength of `6000 Å is 3.32 xx 10^(-19) J` , the photon energy for a wavelength of `4000 Å` will be

A

`1.11 xx 10^(-19)j`

B

`2.22 xx 10^(-19)j`

C

`4.44 xx 10^(-19)j`

D

`4.8 xx 10^(-19) j`

Text Solution

Verified by Experts

The correct Answer is:
4
`E=hc//lambdaorEprop1//lambda,so E_(2)=E_(1)xxlambda_(1)xxlambda_(2)`
`=3.2xx10^(-19)xx6000//4000=4.8xx10^(=-19)j.`
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Knowledge Check

  • If the energy of a photon corresponding to a wavelength 600 nm is 3.32xx10^(-19)J , then energy of a photon of wavelength 400 nm will be

    A
    1.4 eV
    B
    4.9 eV
    C
    3.1 eV
    D
    1.6 eV

  • The enegy of photon corresponding to a radiatio of wavelength 600 nm is 3.32xx10^(-19)J . The energy of a photon corresponding to a wavelength of 400 nm is

    A
    `2.22xx10^(-19)J`
    B
    `4.44xx10^(-19)J`
    C
    `1.11xx10^(-19)J`
    D
    `4.98xx10^(-19)J`

  • What will be the energy of a photon which corresponds to the wavelength of 0.50 Å?

    A
    `3.98xx10^(-15)J`
    B
    `3xx10^(15)J`
    C
    `3.9xx10^(8)J`
    D
    `3xx10^(-34)J`

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