Dimensions of magnetic permeability is :

Options

A. `MLT^(2)A^(-2)`
B. `ML^(-1)T^(-2)A^(-2)`
C. `ML^(-2)T^(-2)A^(2)`
D. `MLT^(-2)A^(-2)`

Explanation

To find the dimensions of magnetic permeability, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Unit of Magnetic Permeability**:
The unit of magnetic permeability (μ) is given as Newton per Ampere squared (N/A²).

2. **Break Down the Unit**:
We know that:
- 1 Newton (N) is defined as \( \text{kg} \cdot \text{m/s}^2 \).
- Therefore, the unit of magnetic permeability can be expressed as:
\[ \text{μ} = \frac{\text{N}}{\text{A}^2} = \frac{\text{kg} \cdot \text{m/s}^2}{\text{A}^2} \]

3. **Express in Terms of Dimensions**:
Now, we can write the dimensions of each component:
- Mass (kg) has the dimension [M].
- Length (m) has the dimension [L].
- Time (s) has the dimension [T].
- Electric current (A) has the dimension [I].

Thus, substituting these into the expression for magnetic permeability:
\[ \text{μ} = \frac{[M] \cdot [L]}{[T]^2 \cdot [I]^2} \]

4. **Combine the Dimensions**:
Therefore, the dimensions of magnetic permeability can be expressed as:
\[ [μ] = [M] \cdot [L] \cdot [T]^{-2} \cdot [I]^{-2} \]

### Final Answer:
The dimensions of magnetic permeability (μ) are:
\[ [M^1 L^1 T^{-2} I^{-2}] \]