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The solubility of AgCl will be miniumum ...

The solubility of AgCl will be miniumum in

A

`0.1 M Na_(2) SO_(4)`

B

`0.01 M CaCl_(2)`

C

Pure water

D

`0.001 M AgNO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`CaCl_(2)` is strong electrolyte and common ion effect
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Determine the solubility of AgCl (in mole/litre) in water. K_(sp) (AgCl)=1.8 xx 10^(-10) .

In which of the following, the solubility of AgCl will be maximum?

Knowledge Check

  • The solubility of AgCl will be minimum in

    A
    `0.1 M CaCl_2`
    B
    `0.01 M AgNO_3`
    C
    Pure water
    D
    `0.1 M NH_3`
  • Solubility of AgCl will be minimum in

    A
    0.001 M `AgNO_(3)`
    B
    Pure water
    C
    0.01 M `CaCl_(2)`
    D
    0.01 M NaCl
  • In which of the following the solubility of AgCl will be minimum ?

    A
    `0.1 M NaNO_(3)`
    B
    Water
    C
    `0.1 M NaCl`
    D
    `0.1 M NaBr`
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