`CH_3-CH=CH_2overset(HCl)rarr(A)` . A is in the given reaction will be

Options

A. `CH_3-underset(Cl)underset(|)(CH)-CH_3`
B. `CH_3-CH_2-CH_2-Cl`
C. `Cl-CH_2-CH=CH_2`
D. `CH_2=CH_2`

Answer

To solve the given reaction \( CH_3-CH=CH_2 \overset{HCl}{\rightarrow} A \), we will follow these steps:

### Step 1: Identify the Reactant
The reactant is an alkene, specifically propene (\( CH_3-CH=CH_2 \)).

**Hint:** Recognize the structure of the alkene and note the location of the double bond.

### Step 2: Understand the Reaction with HCl
When propene reacts with HCl, the double bond will react with the HCl molecule. HCl dissociates into \( H^+ \) and \( Cl^- \).

**Hint:** Remember that alkenes undergo electrophilic addition reactions with hydrogen halides.

### Step 3: Electrophilic Attack
The double bond in propene acts as a nucleophile and attacks the electrophile \( H^+ \). This can occur at either of the carbon atoms involved in the double bond.

**Hint:** Consider the two possible pathways for the addition of \( H^+ \) to the double bond.

### Step 4: Formation of Carbocations
1. If \( H^+ \) adds to the terminal carbon (C1), we form a primary carbocation at C2.
2. If \( H^+ \) adds to the middle carbon (C2), we form a more stable secondary carbocation at C1.

**Hint:** The stability of carbocations plays a crucial role in determining the major product.

### Step 5: Stability of Carbocations
The secondary carbocation (formed by adding \( H^+ \) to C2) is more stable due to the inductive effect of the adjacent methyl group. Thus, this pathway is favored.

**Hint:** Recall that secondary carbocations are generally more stable than primary carbocations due to hyperconjugation and inductive effects.

### Step 6: Nucleophilic Attack by Chloride Ion
The chloride ion (\( Cl^- \)) will then attack the more stable secondary carbocation, leading to the formation of the product.

**Hint:** The nucleophile will attack the carbocation to form the final product.

### Step 7: Write the Product
The final product \( A \) is \( CH_3-CHCl-CH_3 \), which is 2-chloropropane.

**Hint:** Ensure that you correctly identify the positions of the substituents in the final product.

### Final Answer
The product \( A \) from the reaction \( CH_3-CH=CH_2 \overset{HCl}{\rightarrow} A \) is \( CH_3-CHCl-CH_3 \) (2-chloropropane).

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