The equiangular convex hexagon `ABCDEF` has `AB = 1, BC =4,CD=2, and DE=4`. The area of the hexagon is

In a regular hexagon ABCDEF,vec AB=a,vec BC=b and vec CD=c. Then ,vec AE=

In a regular hexagon ABCDEF, AB=a,BC=b and CD=c. Then, vec(AE) is equal to

Each side of a regular hexagon is 1 cm. The area of the hexagon is

In a regular hexagon ABCDEF, vec(AB)=a, vec(BC)=b and vec(CD) = c. Then, vec(AE) =

In a regular hexagon ABCDEF, prove that AB+AC+AD+AE+AF=3AD.

In a regular hexagon ABCDEF, prove that AB+AC+AD+AE+AF=3AD.

If ABCDEF such that AB=1.2cm and DE=1.4cm. Find the ratio of areas of ABC and DEF.

Suppose ABCDEF is a hexagon such that AB=BC=CD=1 and DE=EF=FA=2. If the vertices A,B,C,D,E,F, are concylic, the radius of the circle passing throught them is-