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When a string fixed between two ends is ...

When a string fixed between two ends is plucked, a wave propagates along the string and reflects at the other end. Find the distance of maximum and minimum displacement of the particle in a wave from its first end, given that the velocity of wave propagation is `330 ms^(-1)` and the frequency of vibration is 1320 Hz.

Text Solution

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`V = 330 ms^(-1), n = 1320 Hz, V = nlamda`
`330 = 1320 lamda`
`lamda = (330)/(1320) , lamda = (1)/(4) = 0.25 m`
Distance of maximum displacement from one end `= (lamda)/(4) = (0.25)/(4) = 0.0625 m = 6.25 m`
Distance of minimum displacement from one end = 0
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