Relative lowering of vapour pressure of al dilute solution of gluscose dissolved in 1kg of water is 0.002.The molality of the solution is

Options

A. `0.004`
B. `0.222`
C. `0.111`
D. `0.021`

Answer

C

Explanation

(c) : Relative lowering of vapour pressure for dilute solution i.e., `(p^(@) -p_(s))/(p^(@)) ~~ (n_(2))/(n_(1))`
Given: `(p^(@)-p_(s))/(p^(@)) = 0.002, n_(1(H_(2)O)) = (1000)/(18)` moles For dilute solution, `n_(2)` is molality `= 0.002 xx = (1000)/(18)` m
= 0.111 m