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Find the difference between the simple interest and the compound interest on Rs. 15000 at 12% per annum for 2 years (in Rs. ).

A

216

B

240

C

180

D

192

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AI Generated Solution

The correct Answer is:
To find the difference between the simple interest (SI) and compound interest (CI) on Rs. 15,000 at 12% per annum for 2 years, we will follow these steps: ### Step 1: Calculate Simple Interest (SI) The formula for Simple Interest is: \[ \text{SI} = \frac{P \times R \times T}{100} \] Where: - \( P = 15000 \) (Principal amount) - \( R = 12 \) (Rate of interest) - \( T = 2 \) (Time in years) Substituting the values: \[ \text{SI} = \frac{15000 \times 12 \times 2}{100} \] \[ \text{SI} = \frac{360000}{100} \] \[ \text{SI} = 3600 \] ### Step 2: Calculate Compound Interest (CI) The formula for Compound Interest is: \[ \text{CI} = P \left(1 + \frac{R}{100}\right)^T - P \] Substituting the values: \[ \text{CI} = 15000 \left(1 + \frac{12}{100}\right)^2 - 15000 \] \[ \text{CI} = 15000 \left(1 + 0.12\right)^2 - 15000 \] \[ \text{CI} = 15000 \left(1.12\right)^2 - 15000 \] \[ \text{CI} = 15000 \times 1.2544 - 15000 \] \[ \text{CI} = 18816 - 15000 \] \[ \text{CI} = 3816 \] ### Step 3: Find the Difference between CI and SI Now, we find the difference: \[ \text{Difference} = \text{CI} - \text{SI} \] \[ \text{Difference} = 3816 - 3600 \] \[ \text{Difference} = 216 \] ### Final Answer The difference between the compound interest and simple interest on Rs. 15,000 at 12% per annum for 2 years is **Rs. 216**. ---

To find the difference between the simple interest (SI) and compound interest (CI) on Rs. 15,000 at 12% per annum for 2 years, we will follow these steps: ### Step 1: Calculate Simple Interest (SI) The formula for Simple Interest is: \[ \text{SI} = \frac{P \times R \times T}{100} \] Where: - \( P = 15000 \) (Principal amount) - \( R = 12 \) (Rate of interest) ...
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