Home
Class 12
MATHS
Using the property of determinants and w...

Using the property of determinants and without expanding, prove that:`|x a x+a y b y+b z c z+c|=0`

Answer

Step by step text solution for Using the property of determinants and without expanding, prove that:|x a x+a y b y+b z c z+c|=0 by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DETERMINANTS

    MODERN PUBLICATION|Exercise NCERT FILE (Exercise 4.3)|9 Videos

  • DETERMINANTS

    MODERN PUBLICATION|Exercise NCERT FILE (Exercise 4.4)|7 Videos

  • DETERMINANTS

    MODERN PUBLICATION|Exercise NCERT FILE (Exercise 4.1)|13 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos

  • DIFFERENTIAL EQUATIONS

    MODERN PUBLICATION|Exercise CHAPTER TEST (9)|12 Videos

Similar Questions

Explore conceptually related problems

Using the property of determinants and without expanding,prove that: det[[x,a,x+ay,b,y+bz,c,z+c]]=0

Using the property of determinants and without expanding, prove that: |b+c q+r y+z c+a r+p z+x a+b p+q x+y|=2|a p x b q y c r z|

Using the property of determinants and without expanding,prove that: det[[0,a,-b-a,0,-cb,c,0]]=0

Using the property of determinants and without expanding,prove that: det[[a-b,b-c,c-ab-c,c-a,a-bc-a,a-b,b-c]]=0

Using the property of determinants and without expanding,prove that: det[[1,bc,a(b+c)1,ca,b(c+a)1,ab,x(a+b)]]=0

Using the property of determinants and without expanding in questions 1 to 7 prove that , |{:(a-b,b-c,c-a),(b-c,c-a,a-b),(c-a,a-b,b-c):}|=0

Using the property of determinants and without expanding in questions 1 to 7 prove that , |{:(x,a,x+a),(y,b,y+b),(z,c,z+c):}|=0

Use the properties of determinant and without expanding prove that |{:(b+c,q+r,y+z),(c+a,r+p,z+x),(a+b,p+q,x+y):}| = 2 |{:(a,p,x),(b,q,y),(c,r,z):}| .

Show without expanding at any stage that: [x,a,x+a],[y,b,y+b],[z,c,z+c]|=0

Without expanding prove that det[[x+y,z,1y+z,x,1z+x,y,1]]=0

Home
Profile