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Given P(x) =x^(4) +ax^(3) +bx^(2) +cx +d...

Given P(x) `=x^(4) +ax^(3) +bx^(2) +cx +d` such that x=0 is the only real root of P'(x) =0 . If P(-1) lt P(1),` then in the interval `[-1,1]`

A

`P(-1)` is the minimum and P(1) is the maximum of P

B

`P(-1)` is not minimum but P(1) is the maximum of P

C

`P(-1)` is the minimum but P(1) is not the maximum of P

D

Neither `P(-1)` is the minimum nor P(1) is the maximum of P.

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Given P(x) =x^(4) +ax^(3) +bx^(2) +cx +d such that x=0 is the only real root of P'(x) =0 . If P(-1) < P(1), then in the interval [-1,1]

    A
    P(-1) is the minimum and P(1) is the maximum of P
    B
    P(-1) is not minimum but P (1)is the maximum of P
    C
    P(-1) is the minimum and P(1) is not the maximum of P
    D
    neither P(-1) is the minimum nor P(1) is the maximum of P
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    A
    `-d//a`
    B
    `d//a`
    C
    `a//d`
    D
    none of these
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