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Analyses shows that FeO has a non-stoich...

Analyses shows that FeO has a non-stoichiometric composition with formula `Fe_(0.95)O_(1.00)`. Give reason.

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In FeO , some `Fe^(2+)` ions are replaced by `Fe^(3)` ions i.e., `3Fe^(2+) -= 2 Fe^(3+)` to maintain electrical neutrality. Hence , due to metal deficiency , the compounds obtained are non-stoichiometric composition with formula `Fe_(0.95)O`.
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STATEMENT -1 : FeO is non-stoichiometric with formula Fe_(0.95)O . STATEMENT -2 : Some Fe^(2+) ions are replaced by Fe^(3+) as 3Fe^(3+) = 2Fe^(3+) to mainatain electrons neutrally .

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