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Analyses shows that FeO has a non-stoich...

Analyses shows that FeO has a non-stoichiometric composition with formula `Fe_(0.95)O_(1.00)`. Give reason.

Text Solution

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In FeO , some `Fe^(2+)` ions are replaced by `Fe^(3)` ions i.e., `3Fe^(2+) -= 2 Fe^(3+)` to maintain electrical neutrality. Hence , due to metal deficiency , the compounds obtained are non-stoichiometric composition with formula `Fe_(0.95)O`.
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Knowledge Check

  • Analysis shows that an oxide ore of nickel has formula Ni_(0.98) O_(1.00) . The percentage of nickel as Ni^(3+) ions is nearly

    A
    2
    B
    96
    C
    4
    D
    98

  • STATEMENT -1 : FeO is non-stoichiometric with formula Fe_(0.95)O . STATEMENT -2 : Some Fe^(2+) ions are replaced by Fe^(3+) as 3Fe^(3+) = 2Fe^(3+) to mainatain electrons neutrally .

    A
    If both the statement are TRUE and STATEMENT -2 is the correct explanation of STATEMENT -1
    B
    If both the statement are TRUE and STATEMENT -2 is NOT the correct explanation of STATEMENT -1
    C
    If STATEMENT -1 is the correcct and TRUE and STATEMENT -2 is FALSE
    D
    If STATEMENT -1 is the correcct and FALSE and STATEMENT -2 is TRUE

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    Why FeO in non-stochiometric with the formula Fe_(0.95)O ?

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    Why NiO and FeO are nonstroichiometric with the formula Ni_(0.98)O and Fe_(0.95)O ?

    Analysis shows that a metal oxide has the empirical formula M_(0.98)O_(1.00) . Calculate the percent- age of M^(2+) and M^(3+) ions in this crystal.

    Analysis shows that a metal oxide has the empirical formula M_(0.96)O_(1.00) . Calculate the percentage of M^(2+) and M^(3+) ions in the sample.

    Analysis shows that nickel oxide has the formula Nio_(0.98)O_(1.00) . What fractions of nickel exist as Ni^(2+) and Ni^(3+) ions ?

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