Niobium crystallises in body-centred cubic structure. If the atomic radius is 143.1 pm, calculate the density of Niobium. (Atomic mass = 93u).

Explanation

`r = (sqrt(3))/(4)a`
`143.1 = (sqrt(3))/(4)a`
a = 330.4 pm
`rho = (zM)/(a^(3)N_(A))`
`rho = (2 xx 93)/((330.4 xx 10^(-10)) xx 6.023 xx 10^(23))`
`p = 8.58 g//cm^(3)`.