Given that the energy of the photons of different colours decreases in the order of VIBGYOR (Violet ` gt ` Indigo `gt` Blue `gt` Green ` gt ` Yellow `gt` Red ) and that if complex absorbs a photon of low energy then it shows colour of high energy photon. If an ion , `M^(2+)`, forms the complexes `[M(H_(2)O)_(6)]^(2+),[MBr_(6)]^(4-), and [M(en)_(3)]^(2+)`. The colours of the complexes, though not necessarily in order, are green, red, and blue. Match the complexes with the appropriate colour. ( Do not use the table of complementry colours for this question )

Options

A. `[MBr_(6)]^(4-) blue, [M(H_(2)O)_(6)]^(2+) green, [M(en)_(3)]^(2+) red `
B. `[MBr_(6)]^(4-)green, [M(H_(2)O)_(6)]^(2+) blue , [M(en)_(3)]^(2+) red `
C. `[MBr_(6)]^(4-) green , [M(H_(2)O)_(6)]^(2+) red, [M(en)_(3)]^(2+) blue`
D. `[MBr_(6)]^(4-) red , [M(H_(2)O)_(6)]^(2+) green , [M(en)_(3)]^(2+) blue`

Answer

A

Explanation

Order of crystal field splitting `en gt H_(2)O gt Br^(-)` so, more stronger ligand will absorb lower wavelength light and reflect back higher wavelength light.