Two particles are executing simple harmonic motion of the same amplitude A and frequency `omega` along the x-axis. Their mean position is separated by distance `X_(0)(X_(0)gt A)`. If the maximum separation between them is `(X_(0)+A)`, the phase difference between their motion is

Options

A. `(pi)/(3)`
B. `(pi)/(4)`
C. `(pi)/(6)`
D. `(pi)/(2)`.

Answer

A

Explanation

Let `x_(1)=A sin omega t` and `x_(2)=A sin (omega t+phi)`
`x_(2)-x_(1)=2A cos (omegat+(phi)/(2))sin""(phi)/(2)`
But 2A `sin""(phi)/(2)=Aimpliesphi=(pi)/(3)`
Correct chice : (a).