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During the process : O(2)+e^(-)rarrO(2)^...

During the process : `O_(2)+e^(-)rarrO_(2)^(-)`, the electron in added to the …………… MO .

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To determine which molecular orbital (MO) the electron is added to during the formation of \( O_2^- \) from \( O_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Number of Electrons**: - Oxygen (O) has an atomic number of 8, so \( O_2 \) has a total of \( 2 \times 8 = 16 \) electrons. When an additional electron is added to form \( O_2^- \), the total becomes 17 electrons. 2. **Write the Molecular Orbital Configuration for \( O_2 \)**: ...
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During the change : O_(2)rarrO_(2)^(+)+e^(-) , bond order changes from …………….to …………….

During the change of \(O_{2}\) to \(O_{2}^{-}\) the newly added electron enters into - orbital (A) \(\sigma^{*}_{2P_{2}}\) (B) \(\pi_{2P_{x}}\) (C) \(\pi^{*}_{2P_{x}}\) (D) \(\sigma^{*}_{2P_{z}}\)

Knowledge Check

  • In the process, O_2^+ to O_2^(+2) +e the electron lost is from

    A
    Bonding `pi `- orbital
    B
    Antiboonding `pi`-orbital
    C
    `2p_(z)` orbital
    D
    `2p_(x)` orbital

  • During the change of O_(2) to O_(2)^(-) , the incoming electron goes to the orbital:

    A
    `pi2 p_(y)`
    B
    `sigma^(*)2p_(z)`
    C
    `pi^(*)2p_(x)`
    D
    `pi2p_(x)`

  • During change of NO^(+) rarr NO , the electron is added to

    A
    `sigma`-orbital
    B
    `pi`-orbital
    C
    `sigma^("*")`-orbital
    D
    `pi^("*")`-orbital.

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    In forming (i) N_(2) rarrN_(2)^(o+) and O_(2)rarrO_(2)^(o+) the electrons respectively removed from .

    During change of O_(2) to O_(2)^(2-) ion, the electrons add on which of the following orbitals ?

    During change of NO^(+)to NO , the electron is added to

    During change of O_2 to O_2^(-) ion, the electron adds on which one of the following orbitals?

    In the reaction, M+O_(2)to MO_(2) (superoxide), the metal M is

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