A comerical sample of hydrogen peroxide is labelled as 10 volume its percentage strength
A
0.03
B
0.01
C
0.09
D
0.1
Text Solution
Verified by Experts
The correct Answer is:
A
10 volume `H_(2)O_(2)` means 1L of `H_(2)O_(2)` gives 10 L `O_(2)` at STP according to equation `2H_(2)O_(2)rarr2H_(2)O+O_(2)` 2mole `H_(2)O_(2)` give 1 mol `therefore` 10 L of `O_(2)` at STP is obtained from `H_(2)O_(2)` `=(2)/(22.4)xx10 mol H_(2)O_(2)` =0.89 mol `H_(2)O_(2)` `therefore` 0.89 mol `H_(2)O_(2)` is present in 1L solution Assuming density of solution as 1g `mL^(-1)` 1 L solution =1000g Mass of `H_(2)O_(2)=0.89xx34=30.26 g` percent strength of `H_(2)O_(2)` `=("mass of" H_(2)O_(2)(g))/("mass of solution" (g))xx100` `=(30.26)/(1000)xx100=3.026% `
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