A comerical sample of hydrogen peroxide is labelled as 10 volume its percentage strength

Options

A. 0.03
B. 0.01
C. 0.09
D. 0.1

Answer

A

Explanation

10 volume `H_(2)O_(2)` means 1L of `H_(2)O_(2)` gives 10 L `O_(2)` at STP according to equation
`2H_(2)O_(2)rarr2H_(2)O+O_(2)`
2mole `H_(2)O_(2)` give 1 mol
`therefore` 10 L of `O_(2)` at STP is obtained from `H_(2)O_(2)`
`=(2)/(22.4)xx10 mol H_(2)O_(2)`
=0.89 mol `H_(2)O_(2)`
`therefore` 0.89 mol `H_(2)O_(2)` is present in 1L solution
Assuming density of solution as 1g `mL^(-1)` 1 L solution =1000g
Mass of `H_(2)O_(2)=0.89xx34=30.26 g`
percent strength of `H_(2)O_(2)`
`=("mass of" H_(2)O_(2)(g))/("mass of solution" (g))xx100`
`=(30.26)/(1000)xx100=3.026% `