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29.5mg of an organic compound containing...

`29.5mg` of an organic compound containing nitrogen was digested according to Kjeldahl's method and the evolved ammonia was absorbed in `20mL` of `0.1M HCl` solution. The excess of for complete neutralization. The percentage of nitrogen in the compound is

A

`23.7`

B

`29.5`

C

`59.0`

D

`47.4`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset((HCl))(M_(1)V_(1))=underset((NaOH))(M_(2)V_(2))`
`0.1xxV=0.1xx15`
`V_(HCl)=15ml`
`:.` Volume of `HCl` used by `NH_(3)`
`=20-15=5ml`
`%` of `N=(1.4NV)/(W)`
`N=` Normality of acid used
`V=` Volume of acid used
`W=` wt. of organic compound
For `HCl`, normality `=` Molarity ( `:.` Basicity is `1`)
`%` of `N=(1.4xx0.1xx5)/(29.5xx10^(-3))=23.73%`
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Knowledge Check

  • 29.5 mg of an organic compound containing nitrogen was -digested according to Kjeldahl's method and the evolved ammonia was absorbed in 20 mL of 0-1 M HCl solution. The excess of the acid required 15 mL of 0-1 M NaOH solution for complete neutralization. The percentage of nitrogen in the compound is

    A
    47.4
    B
    23.7
    C
    29.5
    D
    59

  • For the estimation of nitrogen, 1.4 g of an organic compound was digested by Kjeldahl method and the evolved ammonia was absorbed in 60 mL of sulphuric acid. The unreacted acid required 20 mL of M/10 sodium hydroxide for complete neutralisation. The percentage of nitrogen in the compound is

    A
    `6%`
    B
    `10%`
    C
    `3%`
    D
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  • For the estimation of nitrogen 1.4g of an organic compound was digested by Kjeldahl method and the evaloed ammonia was absorbed in 60mL of (M)/(10) sulphuric acid. The unreacted acid required 20mL of (M)/(10) sodium hydroxide for complete neutralisation . The percentage of nitrogen in the compound is

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    C
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